Pad a vector to get matrix

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Mori
Mori 2016-7-26
编辑： Andrei Bobrov 2016-7-26
I have a matrix A like above, how I can get matrix B as result of rotated matrix A in space?

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采纳的回答

Mori
Mori 2016-7-26
A=[10 12 3 34 5]
B=A(1,1)
numel(A)
for i=2:1:numel(A)
B=padarray(B,[1,1],A(1,i))
end

更多回答（1 个）

Andrei Bobrov
Andrei Bobrov 2016-7-26
编辑：Andrei Bobrov 2016-7-26
A = 5:-1:0;
n = numel(A);
B = zeros(2*n-1);
B(n,n) = 1;
B = A(bwdist(B,'chessboard') + 1)
or without Image Processing Toolbox
A = [10 12 3 34 5];
n = numel(A);
[ii,jj] = ndgrid(1:2*n-1);
B = A(max(abs(ii-n),abs(jj-n))+1);
or
A = [10 12 3 34 5];
n = numel(A);
p = 1:2*n-1;
z = toeplitz(p,p);
B = A((z + z(end:-1:1,:))/2);

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