Could someone please explain...

Question

Alex 2012-2-21

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/29841-could-someone-please-explain

编辑： mark 2013-10-19

...the following error? I've looked in the help files and in previous questions to no avail. I am setting up an iteration as follows:

data = csvread('results_n_solve.csv');
assert (size(data, 2) == 1, ...
      'Input data must have exactly one column.');
    nsys = size(data, 1);
       syms n1
       S = n1;
       y  = 450;
       n0 = 1;
       n2 = 4.676;
       k2 = .091;
       d1 = 300;
for k = 1 : nsys
      F = r_dat(data((k-1) + (1:1), 1:end));
      S(k,:) = solve(F);
end

Where the data is a 1 column by 101 row matrix. The function file r_dat is as follows:

function F = r_dat
theta = (2.*pi().*n1.*d1)./y;
      a = n0.*n1 + n0.*n2 - n1.^2 - n1.*n2 + n0.*n1.*cos(theta) - n0.*n2.*cos(theta) + (n1.^2).*cos(theta) - n1.*n2.*cos(theta) + n0.*k2.*sin(theta) + n1.*k2.*sin(theta);
      b = n1.*k2 - n0.*k2 + n0.*k2.*cos(theta) + n1.*k2.*cos(theta) - n0.*n1.*sin(theta) + n0.*n2.*sin(theta) - (n1.^2).*sin(theta) + n1.*n2.*sin(theta);
      c = n0.*n1 + n0.*n2 + n1.^2 + n1.*n2 + n0.*n1.*cos(theta) - n0.*n2.*cos(theta) - (n1.^2).*cos(theta) + n1.*n2.*cos(theta) + n0.*k2.*sin(theta) - n1.*k2.*sin(theta);
      d = n0.*k2.*cos(theta) - n1.*k2.*cos(theta) - n0.*k2 - n1.*k2 - n0.*n1.*sin(theta) + n0.*n2.*sin(theta) + (n1.^2).*sin(theta) - n1.*n2.*sin(theta);
      F = @(x) (1./((c.^2+d.^2).^2)).*(((a.*c + b.*d).^2) + ((b.*c - a.*d).^2)) - x(1);
end

Which is sloppy yet functional (hopefully). When I run this, I receive the following error:

Error using ==> r_dat Too many input arguments.

Error in ==> n_solve at 36 F = r_dat(data((k-1) + (1:1), 1:end));

Error in ==> run at 74 evalin('caller',[script ';']);

So, what does it mean by "too many input arguments"? I don't know what its telling me, so I don't know how to begin to fix it. I've tried playing around with all the variables that are involved, but nothing changes.