finding elements in a matrix`

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Ananya Malik
Ananya Malik 2016-8-16
编辑： Thorsten 2016-8-16
I have a a matrix A= [1 3 10; 1 8 10; 2 4 9] and an array x = [2 9]. i want to check if x is present in a single row of A. In this case it is true, so continue. Can anyone help? TIA.

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Azzi Abdelmalek
Azzi Abdelmalek 2016-8-16
编辑：Azzi Abdelmalek 2016-8-16
A= [1 3 10; 1 8 10; 2 4 9]
x=[ 2 9]
for k=1:size(A,1)
idx=all(ismember(x,A(k,:)));
if idx
break
end
end
idx
  1 个评论
Ananya Malik
Ananya Malik 2016-8-16
编辑：Ananya Malik 2016-8-16
Thanks @Azzi Abdelmalek for the solution. However I have one more query. If I have X=[1 2; 3 9; 3 10; 2 4] and A. If I run the code
for i = 1: length(X(:,1))
x= X(i,:);
for k=1:size(A,1)
idx=all(ismember(x,A(k,:)));
if idx
break;
else
s=[s; x 0];
end
end
end
The output I get is s=[1 2 0;1 2 0; 1 2 0;3 9 0; 3 9 0;3 9 0;2 4 0;2 4 0]. The result i want is s= [1 2 0; 3 9 0].
Can you please help.

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更多回答（1 个）

Thorsten
Thorsten 2016-8-16
编辑：Thorsten 2016-8-16
X=[1 2; 3 9; 3 10; 2 4]
x = [2 9];
X = X(any(ismember(X, x),2), :);
s = [X zeros(size(X,1), 1)];
You also keep the last row, because it contains a 2, a number present in x.

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