Convert for loop to vector multiplication.

1 次查看(过去 30 天)
Hello Friends,
I have the following:
A = [1 2 3;
4 5 6;
7 8 9];
B = [10 11 12;
13 14 15];
[N1, D1] = size(A);
[N2, D2] = size(B);
for i = 1:N2
diffs = bsxfun(@minus, A, B(i, :));
dists(:, i) = sqrt(sum(diffs.^2, 2));
How can I replace the 2nd line in for loop in order to write it in a vector form? I have tried something like this:
for i = 1:N2
diffs = bsxfun(@minus, A, B(i, :));
dists = sqrt(diffs.*diffs);
But the two results are different. I am trying to achieve the following:
distance = sqrt((A-B).*(A-B))
which should be the Euclidean distance. I want to keep it as presented above without changing format to compute distance or using repmat, etc.

回答(1 个)

Walter Roberson
Walter Roberson 2016-8-17
dists = sqrt(diffs.*diffs);
is not going to be doing any sum. You might be thinking of the * operator instead of the .* operator.
You could also look at dot() and norm()
  1 个评论
hello_world 2016-8-17
编辑:hello_world 2016-8-17
Can you elaborate please with a work example using * so that the two results be the same.



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