plotting in a loop - new figure window

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Richard
Richard 2012-2-23
编辑： Matt J 2013-10-22
The following example produces a subplot of the 3 variables below (located in a structure):
clear all
Data.S1 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
Data.S2 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
Data.S3 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
% Data.S4 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
% Data.S5 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
% Data.S6 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
a = fieldnames(Data);
cmap = hsv(length(a));
for i=1:length(fieldnames(Data));
subplot(3,1,i)
plot(Data.(a{i}).data1,'color',cmap(i,:));
end
If I were to uncomment the last three lines of 'Data' hence have 6 variables in total, how would I alter the loop to produce subplots of all of the data. Keeping in mind that the number of subplots in each figure should not exceed 3 (plots get too small). So, from this example I should have 2 figure windows with 3 subplots in each. How would I go about doing this?
Amended:
clear all
Data.S1 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
Data.S2 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
Data.S3 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
Data.S4 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
Data.S5 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
Data.S6 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
a = fieldnames(Data);
figure(1)
for i=1:3;
subplot(3,1,i);
plot(Data.(a{i}).data1);
end
figure(2)
for i=1:3
for ii=3:6;
subplot(3,1,i);
plot(Data.(a{ii}).data1);
end
end
This is the outcome I need.

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采纳的回答

Kevin Holst
Kevin Holst 2012-3-2
how about:
clear all
Data.S1 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
Data.S2 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
Data.S3 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
Data.S4 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
Data.S5 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
Data.S6 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
Data.S7 = struct('data1',rand(12,1),'data2',rand(12,1),'data3',rand(12,1));
a = fieldnames(Data);
numPlots = length(a);
numFigs = ceil(numPlots/3);
for i = 1:numFigs
figure
for j = 1:3
plotNum = j + 3*(i-1);
if plotNum <= numPlots
subplot(3,1,j)
plot(Data.(a{plotNum}).data1)
end
end
end

更多回答（2 个）

Walter Roberson
Walter Roberson 2012-2-23
pwide = 3; %max subplots wide
nfields = length(a);
pslots = pwide * ceil(nfields / pwide);
for i - 1 : nfields
subplot(pslots, ceil(i / pwide), 1 + mod(i-1, pwide))
plot(Data.(a{i}).data1,'color',cmap(i,:));
end
  2 个评论
Richard
Richard 2012-2-23
this doesn't produce 2 figure windows. What I want is figure(1);subplot(313) and figure(2);subplot(313) if that makes sense.
Walter Roberson
Walter Roberson 2012-2-23
pwide = 3; %max subplots wide
nfields = length(a);
for i - 1 : nfields
if mod(i,pwide) == 1; figure; end
subplot(pwide, ceil(i / pwide), 1 + mod(i-1, pwide))
plot(Data.(a{i}).data1,'color',cmap(i,:));
end

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Image Analyst
Image Analyst 2012-2-23
So just have it do this:
for i=1:length(fieldnames(Data));
figure;
subplot(3,1,3); % Note 3,1,3, not 3,1,i like before.
plot(Data.(a{i}).data1,'color',cmap(i,:));
end
That will give you a new figure each iteration and put your image in the bottom third of the figure like you asked for in your comment to Walter.
  2 个评论
Richard
Richard 2012-2-24
I'm sorry, my question wasn't clear enough, its not that I need every plot to be subplot(313) I was using this as an example of the largest number of subplots per figure window (stupid I know). So, if I have 6 vectors need plotting, I want the first 3 plots to be in figure window 1 i.e. vector 1 in subplot(311), vector 2 in subplot (312), vecotr 3 in subplot (313), vector 4 in figure(2) subplot(311)... and so on. So, say that I had 11 vectors, the code should produce 3 figure windows each with 3 subplots and the fourth figure window with 2 subplots.
Richard
Richard 2012-2-24
I've amended the question to show the desired outcome.

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