Using the struct function with a for loop

Question

Meghan 2016-8-25

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https://ww2.mathworks.cn/matlabcentral/answers/300848-using-the-struct-function-with-a-for-loop

编辑： Stephen23 2016-8-25

Hello

I have a matrix that is 89x4. I've used a for loop to extract each row of data to make 89 new matrices. I needed to do that because each row is a new nodal point in my data set. What I need to do now is make a structure array with a list of each nodal point.

My original for loop is

for n=1:89;
    eval(['Node_' num2str(n) '=nodeXYZ(n,:);']);
end

That gives me each matrix (Node_1 to Node_89). I've tried to used dynamics naming within a for loop to make a different array within a structure for each node but I keep getting errors. Or when it works its completely wrong.

Triangle_points.node_data.nodes=struct('Node',Node_1);
 for field='Node';
   Triangle_points.node_data.nodes.(field)=Node_1;
 end

That is along the lines of what I'm trying. Its probably very wrong, which is why I need the help. I really don't want to have to write out 89 different fields and values! Any suggestions or help on this would be appreciated.

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Stephen23 2016-8-25

编辑：Stephen23 2016-8-25

@Meghan: using eval is a buggy, slow, and obfuscated way to write code. Learn to code without it and your code will be faster, better, neater, and easier to read. There are so many tools that help you when you do not use eval, such as code hinting, tab completion, variable highlighting, help, syntax error highlighting, etc, etc,, which help you to write good code none of them work when you use eval! Summary: learn to write code without eval.

http://www.mathworks.com/help/matlab/matlab_prog/string-evaluation.html

https://www.mathworks.com/matlabcentral/answers/196952-how-to-create-new-variables-in-batches-with-strcat

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Answer 1

Adam 2016-8-25

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/300848-using-the-struct-function-with-a-for-loop#answer_232736

编辑：Adam 2016-8-25

在 MATLAB Online 中打开

Something like

for n = 1:89
   fieldName = strcat( 'Node_', num2str( n ) );
   Triangle_points.node_data.nodes.( fieldName ) = nodeXYZ(n,:);
end

should give you the output you are looking for without needing to go via 89 unwanted variables. I would question why you would want this setup though.

You could instead use an array of 89 structures, each just with a 'node' field or simply keep your data in its original array as the best option. Most maths that you would want to do can be done on data that just sits in a single neat multi-dimensional numeric array. Moving away from one numeric array into 89 of them or a struct with 89 fields or 89 structs with 1 field all just make subsequent operations all the more complicated and inefficient.

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Meghan 2016-8-25

Thank you :) that worked. I would rather not separate the data this way either but I've been asked to do it. It feeds into a model which run in Java so I think he wants it this way for that reason, not too sure!

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