If A is a matrix, A(:) produces the columns in a vector. Is there a parallel function for rows?
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A=[1,2,3;4,5,6;7,8,9]. Then A(:) returns [1;2;3;4;5;6;7;8;9]. Is there an operator that will produce [1,2,3,4,5,6,7,8,9]?
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James Tursa
2016-8-26
编辑:James Tursa
2016-8-26
First, I assume your example result is a typo, since A(:) will return the elements in column order, not row order. E.g.,
>> A=[1,2,3;4,5,6;7,8,9]
A =
1 2 3
4 5 6
7 8 9
>> A(:)
ans =
1
4
7
2
5
8
3
6
9
To get them out in row order, transpose A first. E.g.
>> A=[1,2,3;4,5,6;7,8,9]
A =
1 2 3
4 5 6
7 8 9
>> reshape(A',[],1)
ans =
1
2
3
4
5
6
7
8
9
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James Tursa
2016-8-26
编辑:James Tursa
2016-8-26
Ummm ... that was a direct copy from my MATLAB command window, and the order is clearly 1,2,3,4,5,6,7,8,9 as shown. If you want the result as a row instead of a column, then simply:
reshape(A',1,[])
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