Syntax x = fmin('fun',x1,x2)

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work wolf
work wolf 2016-8-31
评论： Star Strider 2016-9-1
Syntax
x = fmin('fun',x1,x2)
x = fmin('fun',x1,x2,options)
x = fmin('fun',x1,x2,options,P1,P2, ...)
[x,options] = fmin(...)
are not working by matlab? the message from matlab as follows as:
>> f =@(x) x.^3-2*x-5;
>> x = fmin('f', 0, 2)
Undefined function 'fmin' for input arguments of type 'char'.
Did you mean:
>> x = min('f', 0, 2)
Error using min
MIN with two matrices to compare and a working dimension is not supported.
>> x = fminbnd('f', 0, 2)
Cannot find an exact (case-sensitive) match for 'f'

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采纳的回答

Star Strider
Star Strider 2016-8-31
You’re almost there.
This works:
f =@(x) x.^3-2*x-5;
x = fminbnd(f, 0, 2)
x =
816.4968e-003
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work wolf
work wolf 2016-9-1
Relly , thank you sooooo much
Star Strider
Star Strider 2016-9-1
As always, my pleasure!

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更多回答（1 个）

Walter Roberson
Walter Roberson 2016-8-31
http://www.mathworks.com/help/releases/R13sp2/techdoc/ref/fmin.html
"Note: The fmin function was replaced by fminbnd in Release 11 (MATLAB 5.3). In Release 12 (MATLAB 6.0), fmin displays a warning message and calls fminbnd."
If you are using MATLAB 5.3 or earlier, that is important information for us to know. If you are using something that old, you would use
x = fmin('f', 0, 2)
but you would also have to have created file f.m with content
function y = f(x)
y = x.^3-2*x-5;
  2 个评论
work wolf
work wolf 2016-8-31
x = fmins('fun',x0)
x = fmins('fun',x0,options)
x = fmins('fun',x0,options,[],P1,P2, ...)
[x,options] = fmins(...)
and
z = fzero('fun',x) z = fzero('fun',x,tol)
z = fzero('fun',x,tol,trace)
z = fzero('fun',x,tol,trace,P1,P2,...)
thankx, if the fmin function was replaced by fminbnd, what were replaced fmins and fzero?
Steven Lord
Steven Lord 2016-8-31
fmins -> fminsearch
fzero -> fzero

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