Getting error Operands to the || and && operators must be convertible to logical scalar values.

Question

Astrik 2016-8-31

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/301517-getting-error-operands-to-the-and-operators-must-be-convertible-to-logical-scalar-values

评论： Param Siddharth 2020-4-23

采纳的回答： Star Strider

在 MATLAB Online 中打开

I have to check the arguments of my function for a number of cases. The function passes all tests besides the arguments

12, 3, [3 4], 5

The code is as follows

function dd= day_diff(month1, day1, month2, day2)
if month1<1 || month2<1 || day1<=0|| day2<=0 || rem(month1,1)~=0 ||rem(day1,1)~=0 ||  rem(month2,1)~=0 || rem(day2,1)~=0 || isscalar(month1)~=1 || isscalar(month2)~=1 || isscalar(day1)~=1 || isscalar(day2)~=1 
    dd=-1;
elseif (month1==2 && day1==29) || (month2==2 && day2==29)
     dd=-1;
elseif (eomday(2015,month1)==30 && day1==31) ||(eomday(2015,month2)==30 && day2==31)
    dd=-1;

The error I get

>> day_diff(12, 3, [3 4], 5)
Operands to the || and && operators must be convertible to logical
scalar values.
Error in day_diff (line 2)
if (month1<1 || isscalar(month1)~=1) || (month2<1
||isscalar(month1)~=1) ||  day1<=0|| day2<=0 || rem(month1,1)~=0
||rem(day1,1)~=0 ||  rem(month2,1)~=0 || rem(day2,1)~=0 ||
isscalar(day1)~=1 || isscalar(day2)~=1

Any help will be appreciated.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Star Strider 2016-8-31

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/301517-getting-error-operands-to-the-and-operators-must-be-convertible-to-logical-scalar-values#answer_233280

The short-circuit operators don’t work with vector arguments. Replace them with single ‘|’ and ‘&’ and see if that solves the problem.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

Answer 2

Steven Lord 2016-8-31

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/301517-getting-error-operands-to-the-and-operators-must-be-convertible-to-logical-scalar-values#answer_233281

在 MATLAB Online 中打开

month2 = [3 4];
z = month2 < 1

Is z a logical scalar value? In order to be a logical scalar value, it must be BOTH logical (check this with the class function) AND scalar (check with isscalar.)

Reorder your error checking to check that the input are scalar first. Once you know your inputs are scalar, then you can check their values.