TAYLOR METHOD OF ORDER 3 ERROR

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LOKESH
LOKESH 2012-2-25
I want to solve the following equation using taylor's method of order 3. The equation is F=A(y-x). Initially y=-10.058 and x=0.368. A is constant with value equal to 35.
the code is:
M=183;
h = 0.001;
A = 35;
XX(1) = -10.058;
YY(1) = 0.368;
for i=1:((M^2)/3)
F=A*(YY(i)-XX(i));
H(i)=taylor(F,3,XX);
end;
It gives me following error--->
??? Undefined function or method 'taylor' for input arguments of type 'double'.
Error in ==> tay at 19 H(i)=taylor(F,3,XX);
ANY SUGGESTION OR SOLUTION..

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回答（1 个）

Walter Roberson
Walter Roberson 2012-2-25
taylor() is a routine from the symbolic toolkit, and it must be provided with a symbolic expression that includes at least one variable name. Instead you are trying to call taylor() with a purely numeric value: your F is a purely numeric formula.

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