changing the values

1 次查看（过去 30 天）
FIR
FIR 2012-2-25
编辑： Azzi Abdelmalek 2013-10-25
i have values in
r as
'<=50k' '>50k' '>50k' ; ;
; '>50k'
now i want to replace these values
>50k as 1
<=50 as 0
please help
i read those values from excel sheet
[d r]=xlsread('mydata.xls');in whicg i got those values in r

请先登录，再回答此问题。

采纳的回答

Andrei Bobrov
Andrei Bobrov 2012-2-25
in this case
r = {'<=50k' '>50k' '>50k' '>50k'}
[a n n] = unique(r)
k = {0,1}
rnew = k(n)
or
rnew = cellfun(@(x)x-'0',regexprep(r,{'<=50k' , '>50k'},{'0','1'}))
on FIR comment: try
rnew = regexprep(r,{'<=50k' , '>50k'},{'0','1'})
on Pat comment
r = {'<=50k' '>50k' '>50k' '>50k' 'fg' ''}
rnew = regexprep(r, {'<=50k', '>50k'}, {'0', '1'})
t = ismember(rnew, {'0', '1'})
rnew(t) = cellfun(@(x)x-'0', rnew(t), 'un', 0)
  2 个评论
FIR
FIR 2012-2-25
Andrei error in both
in first i get values more than 1
and in second is get error aS
Error using ==> cellfun
Non-scalar in Uniform output, at index 1, output 1.
Set 'UniformOutput' to false.
Pat
Pat 2012-2-25
it works,but i want that single quotes to be removed for further processing

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by