How do I write the following functions on Matlab x(t) = 2tcos(pi*t) , y(t) = 2sin(pi*t)

8 次查看(过去 30 天)
I keep getting error using * and other errors
  1 个评论
Steven Lord
Steven Lord 2024-3-2
These functions didn't exist when the question was originally asked (they were introduced in release R2018b) but the sinpi and cospi functions may be of use.

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采纳的回答

KSSV
KSSV 2016-9-21
t = 0:0.1:60 ;
x = 2*t.*cos(pi*t) ;
y = 2*sin(pi*t) ;
  2 个评论
Khalid Tewfik
Khalid Tewfik 2016-9-21
this is what I have t = 0:.1:2; x1 = 2*t.*cos(pi*t); y1 = 2*sin(pi*t); plot(x1,y1) but i'm still getting the error message Error using * Inner matrix dimensions must agree.
Error in plotting (line 8) x1 = 2*t*cos(pi*t);

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更多回答(2 个)

Adam
Adam 2016-9-21
t = linspace( 0, 2*pi, 100 );
x = 2 * t .* cos( pi * t );
y = 2 * sin( pi * t );
  2 个评论
Khalid Tewfik
Khalid Tewfik 2016-9-21
this is what I have t = 0:.1:2; x1 = 2*t.*cos(pi*t); y1 = 2*sin(pi*t); plot(x1,y1) but i'm still getting the error message Error using * Inner matrix dimensions must agree.
Error in plotting (line 8) x1 = 2*t*cos(pi*t);
John D'Errico
John D'Errico 2024-3-3
@Khalid Tewfik - too late for this response for you, but you need to see that you used the expression:
2*t*cos(pi*t)
Do you see you used the * operator, instead of the .* operator? The difference if important in MATLAB.

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MD.AL-AMIN
MD.AL-AMIN 2024-3-2
编辑:Walter Roberson 2024-3-3
% Define the signal function
X = @(t) 5 * sin(2*pi*t) .* cos(pi*t - 8);
% Define the range of t
t = linspace(0, 20, 1000); % Adjust the number of points for desired resolution
% Plot the signal
figure;
plot(t, X(t));
% Label axes and title
xlabel('t');
ylabel('X(t)');
title('Signal X(t)');
% Adjust axis limits and grid (optional)
xlim([0, 20]); % Set appropriate x-axis limits
ylim([-5, 5]); % Set appropriate y-axis limits
grid on;

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