Reducing intensity in an image using a function

Question

PenguinForce 2016-10-12

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/306856-reducing-intensity-in-an-image-using-a-function

评论： Image Analyst 2016-10-12

So I'm trying to use mean filtering to process an image. The idea of mean filtering is simply to replace each pixel value in an image with the mean (average) value of its neighbors, including itself.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Walter Roberson 2016-10-12

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/306856-reducing-intensity-in-an-image-using-a-function#answer_238574

https://www.mathworks.com/help/images/ref/medfilt2.html

2 个评论
显示无隐藏无

PenguinForce 2016-10-12

I'm trying to accomplish this without using built in functions like this

Walter Roberson 2016-10-12

http://www.mathworks.com/matlabcentral/answers/38787-what-can-be-programmed-without-any-built-in-functions

请先登录，再进行评论。

Answer 2

Image Analyst 2016-10-12

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/306856-reducing-intensity-in-an-image-using-a-function#answer_238577

在 MATLAB Online 中打开

Try conv2:

windowSize = 3;
kernel = ones(windowSize)/windowSize^2;
filteredImage = conv2(double(grayImage), kernel, 'same');
imshow(filteredImage, []);

This will give an output image where each pixel is the mean of a sliding 3-by-3 window.

2 个评论
显示无隐藏无

Walter Roberson 2016-10-12

conv2 will not give the answer the user wants at the edges, as it will zero pad, but still divide by the windowSize^2. The user wants the edges to only be divided by the number of pixels that are in-bounds.

You can run a correction afterwards -- multiply the edge values by windowSize^2 and then divide by the number of valid neighbours, which would be 6 everywhere except the corners and would be 4 there.

Image Analyst 2016-10-12

Yes, there are boundary/edge effects with filters and there are different ways of handling them. imfilter() is like conv2() but offers more boundary handling options. Unfortunately none of them see to be the "shrinking window" effect like Walter mentioned. For a 3x3 filter (nearest 8 neighbors), only the outermost perimeter layer of edge pixels is affected. So if the outer 1-pixel-wide boundaries are important to you, and you want that "shrinking window" option, you'll have to do like Walter explained. It is possible to do it with nlfilter() or blockproc() but those won't be nearly as fast as conv2() or imfilter() which are highly optimized, so to just fix up one pixel, I wouldn't bother with those.

请先登录，再进行评论。