Plotting just x = 1 over an x and y graph

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Erin W
Erin W 2016-10-13
评论： Erin W 2016-10-13
Howdy howdy howdy,
I have this following code which gives me two out of the three lines I need:
a = 2;
x = linspace(1,100,10);
for i=1:length(x)
y1(i) = 0*(i);
y2(i) = ((a-i).*(1+i))/i;
end
figure
plot(x,y1,x,y2)
I need to plot an additional line on the same plot. That line needs to be x = 1/(a-1) = 1.
Can someone help me?
Cheers! E

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采纳的回答

Walter Roberson
Walter Roberson 2016-10-13
yl = get(gca, 'YLim');
line( [1 1], yl )
This would draw a vertical line the height of the axes. (Note: if you later make the axes taller, the line will not automatically adjust itself.)

更多回答（1 个）

Guillaume
Guillaume 2016-10-13
a = 2;
x = 1:linspace(1, 100, 10);
y = 1:numel(x);
plot(x, [zeros(size(x)); (a-y).*(1+y)./y; repmat(1/(a-1), 1, numel(x))]);
is probably the simplest. The loop is certainly not required.
I don't particularly see the point of the brackets in 0*(i), and even less the point of the multiplication, since y1(i) = 0 would convey exactly the same with better readability.
In your y2 expression, a and i are both scalar, so .* is the same as * and ./ is the same as /, but really you should be consistent.
  1 个评论
Erin W
Erin W 2016-10-13
It's odd because I was getting an error until I put that period in. But MATLAB goofs a lot for me.
I just was playing around with things. I'm not a great coder by any means. But thank you. You have been extremely helpful.

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