how to set an intervall to a given angle?

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Ormia
Ormia 2016-10-18
回答: John 2016-10-18
I have an assignment, where I have to set an intervall for a given angle x to 0<=x<=40pi? How do I do that? The answer is apparently x=0:pi/1000:40*pi, where does pi/1000 come from?

回答(1 个)

John
John 2016-10-18
pi/1000 is the step size between points in the vector starting at 0 and ending at 40*pi.

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