Help with an error

1 次查看（过去 30 天）
Ali
Ali 2012-3-1
Hello,
I want to ask you how can I solve such an error.
The thing is I want a 2-D array that grows.
x has a length n and is a column vector
L is an nxn vector
this is the prototype of the code.
I cant figure out a way to solve such a question
function [Nt,xe,ye]= PopulationProgress(x,L)
%x=[200000,300000,500,1500]'
i=0;
n=length(x);
Nt=Zeros(n,3);
Nt(:,1)=x;
Nt(:,2)=L*Nt(:,1);
while Nt(:,i)= Nt(:,i+1)
i=i+1;
Nt(:,i)=L*Nt(:,i-1);
Nt(:,i+1)=L*Nt(:,i);
end;
ye=i;
xe=Nt(:,i);
Thank you for any suggestions
Best

请先登录，再回答此问题。

采纳的回答

Srinivas
Srinivas 2012-3-1
MATLAB is case sensitive, replace your
Nt = zeros(n,3)
i = 1,
MATLAB does not allow indices to be '0';

更多回答（1 个）

Walter Roberson
Walter Roberson 2012-3-1
In your "while" statement, you need to use "==" rather than "="
  1 个评论
Ali
Ali 2012-3-1
Yup, I figured it out. Yet still I am getting an error.
I don't know why.
Nt=Zeros(n,3);
Nt(:,1)=x; have the same size
I am not sure about the syntax of the coding though.
I want the column to be equal to x.
Is this how am I supposed to do it?

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Number Theory 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by