Problem using quad2d with vector
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Using below code with the variable t doesn't work, matrix dimensions don't agree, if the variable is replaced with a single number it does work (though that's not particularly useful), I've tried replacing it with a loop to no avail.
What am i missing?
lm = 1.75;
Cm = 3.2E6;
fe = 1380;
H = 13.5;
% time and space
y = 0.0;
ro = 0.1;
x = ro;
ts = [0.1 97/24];
Mt = 100;
% t = logspace(log10(ts(1)*86400),log10(ts(2)*86400),Mt); % [s]
t = linspace(ts(1)*86400, ts(2)*86400, Mt); % [s]
% calculated parameters
QL = fe/H;
z = H/2;
Dt = lm/Cm;
r = sqrt(x.^2+y.^2);
T = QL*(1/4/pi/lm)*...
(quad2d(@(f,ze) erfc(sqrt(r^2+ro^2-2*r*ro*cos(f)+(z-ze).^2)...
/2/sqrt(Dt*t))/pi./sqrt(r^2+ro^2-2*r*ro*cos(f)+(z-ze).^2),0,pi,0,H)-...
quad2d(@(f,ze) erfc(sqrt(r^2+ro^2-2*r*ro*cos(f)+(z-ze).^2)...
/2/sqrt(Dt*t))/pi./sqrt(r^2+ro^2-2*r*ro*cos(f)+(z-ze).^2),0,pi,-H,0));
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采纳的回答
KSSV
2016-10-26
You have to take care of element wise operations in that big expression T. As T is very big and clumsy, I have modified it to a loop, as below.
clc; clear all ;
lm = 1.75;
Cm = 3.2E6;
fe = 1380;
H = 13.5;
% time and space
y = 0.0;
ro = 0.1;
x = ro;
ts = [0.1 97/24];
Mt = 100;
% t = logspace(log10(ts(1)*86400),log10(ts(2)*86400),Mt); % [s]
tt = linspace(ts(1)*86400, ts(2)*86400, Mt); % [s]
% calculated parameters
QL = fe/H;
z = H/2;
Dt = lm/Cm;
r = sqrt(x.^2+y.^2);
T = zeros(size(tt)) ;
for i = 1:length(tt)
t = tt(i) ;
T(i) = QL*(1/4/pi/lm)*...
(quad2d(@(f,ze) erfc(sqrt(r^2+ro^2-2*r*ro*cos(f)+(z-ze).^2)...
/2/sqrt(Dt*t))/pi./sqrt(r^2+ro^2-2*r*ro*cos(f)+(z-ze).^2),0,pi,0,H)-...
quad2d(@(f,ze) erfc(sqrt(r^2+ro^2-2*r*ro*cos(f)+(z-ze).^2)...
/2/sqrt(Dt*t))/pi./sqrt(r^2+ro^2-2*r*ro*cos(f)+(z-ze).^2),0,pi,-H,0));
end
Though it is working, it is throwing some warning. I suggest you to check the expression for T.
更多回答(1 个)
Torsten
2016-10-26
There is no other way than to loop over the elements of t and call quad2d for each element separately.
MATLAB's "integral" has the option "ArrayValued=True", but as far as I know, integral2 or quad2d haven't.
Best wishes
Torsten.
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