lsqnonlin: failure in initial user-supplied function

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Emilie Mussard 2016-10-28

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https://ww2.mathworks.cn/matlabcentral/answers/309651-lsqnonlin-failure-in-initial-user-supplied-function

编辑： Matt J 2016-10-28

Dear MATLAB users, I have some troubles with lsqnonlin. I either obtain an error saying: Failure in initial user-supplied objective function evaluation. LSQNONLIN cannot continue. if I use the function as provided below, or obtain an error saying: User-defined Jacobian is not the correct size: the Jacobian matrix should be 3-by-3. if I define the Jacobian as

J = [-TE.*x(2).*e; e+delta; delta];

But I disagree with this because I have only one function with three variables, hence the jacobian should be 1 by 3...

Any idea to help me would be greatly appreciated! Thank you!

My function:

function map = r2PixelFitNonLinDelta(M, TE)
    M = squeeze(M);
    if(size(TE,1) == 1)
        TE = TE';
    end
    options = optimset('Display','off','MaxIter',100,'TolFun',1e-6,'Jacobian','on');
    R2 = 0.08;
    M0 = 1;
    delta0 = 0.09;
    x0 = [R2;M0;delta0];
    map = zeros(size(M,1),size(M,2),numel(x0));
    for y = 1:size(M,1);
        parfor x = 1:size(M,2);
            dat = reshape(M(y,x,:),[numel(TE) 1]);
            map(y,x,:) = lsqnonlin(@(x)fun(x, TE, dat), x0 , [] , [], options);
        end
    end
end
function [F J] = fun(x, TE, M)
    delta = x(3);
    e = exp(-TE.*x(1));
    F = x(2).*(e + delta) - M;
    J = [-TE.*x(2).*e, e+delta, delta];
end

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Matt J 2016-10-28

编辑：Matt J 2016-10-28

I disagree with this because I have only one function

You should probably give us input M,TE with which to test your function, but I see no reason why F as returned by fun(x, TE, M) would be a scalar, as you seem to claim.

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