Power from an image

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captainmariah
captainmariah 2016-11-21
编辑： Walter Roberson 2016-11-21
Hi, I have a certain image with an intensity distribution.
How do I calculate the Power?
Is it correct to take the area * intensity?
How to I estimate the total intensity from the laser beam? sum(sum(image))= 623614876? im a bit confused becuase intensity is usually in unit W/m2 or W/sr? The value deosnt look correct.
My aim is to only take a part of this intensity distribution, and determine the total intensity of this part (a certain angle) by assuming the power is for example 4 W. How much intensity do I have within a certain angle distribution.
Image is gray. It shows the intensity from the laser distribution that has a certain rectangular shape. I don't know what the maximal pixelvalue is, but it doesn't seem saturated. The image is 2048 x 2048 pixels.
Thanks in advance!

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回答（1 个）

Walter Roberson
Walter Roberson 2016-11-21
编辑：Walter Roberson 2016-11-21
  15 个评论
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Walter Roberson
Walter Roberson 2016-11-21
Better yet a whole series of known powers.
But you mention that you do not have the original images. Is the implication that you cannot run calibration tests?
Image Analyst
Image Analyst 2016-11-21
I agree with Walter and Guillaume: your best bet is to take pictures of known non-saturated patterns of known powers and basically build up a lookup table or function that gives you power out as a function of total integrated gray level in. That should work as long as you don't change the exposure time per frame (per video or still frame) after making this calibration function.

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