"Attempt to execute SCRIPT fft2 as a function" Don't know how to solve this mistake. fft2 is a function of matlab. Thanks!

Question

Felipe neut 2016-11-21

1
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/313352-attempt-to-execute-script-fft2-as-a-function-don-t-know-how-to-solve-this-mistake-fft2-is-a-funct

回答： Star Strider 2016-11-21

clc;clear;
datos = imread('/users/Desktop/arroz.png');
U = im2double(datos);
[N,M] = size(datos);
P = 2*N;
Q = 2*M;
K1 = [0.0509 0.1238 0.0509;0.1238 0.3012 0.1238;0.0509 0.1238 0.0509];
K2 = [0.4444 0.1111 0.4444;0.1111 -2.2222 0.1111; 0.4444 0.1111 0.4444];
h1 = conv2(U,K1,'same');
h2 = conv2(U,K2,'same');
figure;
subplot(1,2,1);imshow(h1,[]);title('Convolución con kernel K1');
subplot(1,2,2);imshow(h2,[]);title('Convolución con kernel K2');
ZP1 = zeros(P,Q);
ZP2 = zeros(P,Q);
ZP1(1:N,1:M) = h1;
ZP2(1:N,1:M) = h2;
DFT1 = fft2(ZP1);
DFT2 = fft2(ZP2);
figure;
subplot(1,2,1);imshow(log(abs(DFT1))+1,[]);title('DFT de imagen convolucionada con K1');
subplot(1,2,2);imshow(log(abs(DFT2))+1,[]);title('DFT de imagen convolucionada con K2');