question about how to avoid using eval

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Baozai
Baozai 2016-11-22
评论： Baozai 2016-11-22
Hello, all.
I got to know that using "eval" is not efficient and may cause several problems. I have used "eval" a lot in my previous codes.
If I want to replace the following expression without using "eval", would anyone help me one this? Thank you very much.
for jjjj=1:5
for iiii=1:40
for kkkk=1:3
x1(kkkk,:) = (1:10)*kkkk;
eval(['Resp.Phi',num2str(jjjj),'.Mu',num2str(iiii),'.Respx1(kkkk,:) = x1(kkkk,:);']);
end
end
end

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采纳的回答

Walter Roberson
Walter Roberson 2016-11-22
Resp.(sprintf('Phi%d',jjjj).(sprintf('Mu%d',iiii)),.Respx1(kkkk,:) = x1(kkkk,:);
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Walter Roberson
Walter Roberson 2016-11-22
You are right,
Resp.(sprintf('Phi%d',jjjj)).(sprintf('Mu%d',iiii)).Respx1(kkkk,:) = x1(kkkk,:);

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更多回答（1 个）

KSSV
KSSV 2016-11-22
iwant = cell(5,40,3) ;
for jjjj=1:5
for iiii=1:40
for kkkk=1:3
x1(kkkk,:) = (1:10)*kkkk;
iwant{jjjj,iiii,kkkk}= ['Resp.Phi',num2str(jjjj),'.Mu',num2str(iiii),'.Respx1(kkkk,:) = x1(kkkk,:);'] ;
end
end
end
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KSSV
KSSV 2016-11-22
编辑：KSSV 2016-11-22
Resp = struct ;
for jjjj=1:5
for iiii=1:40
for kkkk=1:3
x1(kkkk,:) = (1:10)*kkkk;
% iwant{jjjj,iiii,kkkk}= ['Resp.Phi',num2str(jjjj),'.Mu',num2str(iiii),'.Respx1(kkkk,:) = x1(kkkk,:);'] ;
end
for llll = 1:3
Resp(jjjj).Phi1(iiii).Mu1(llll).Respx1 = x1 ;
end
end
end
Resp(1).Phi1(1).Mu1
Baozai
Baozai 2016-11-22
This one also works, thank you very much for your help.

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