Write a function called day_diff that takes four scalar positive integer inputs, month1, day1, month2, day2. These represents the birthdays of two children who were born in 2015. The function returns a positive integer scalar that is equal to the dif
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I can't deal it anymore. I have trouble to check an integer number or an array number in order to input argument in this problem .
function dd = day_diff(month1, day1, month2, day2)
if (month1 && day1 >0)&&(month1
if true
% code
end <= 12)&&(month2 && day2 >0) && month2 <= 12
if isinteger(month1 &&
if (month1 == 1 && month2 == 1)||(month1 == 3 && month2 == 3)||(month1 == 5 && month2 == 5)||(month1 == 7 && month2 == 7)||(month1 == 8 && month2 == 8)||(month1 == 10 && month2 == 10)||(month1 == 12 && month2 == 12) && day1<=31 && day2<=31
if day1 == day2
total1 = day1;
total2 = day2;
elseif day1 ~= day2
total1 = max(day1,day2);
total2 = min(day1,day2);
end
elseif (month1 == 4 && month2 == 4) ||(month1 == 6 && month2 == 6)||(month1 == 9 && month2 == 9)||(month1 == 11 && month2 == 11) % months have 30 days
if day1 == day2 && day1<=30 && day2<30
total1 = day1;
total2 = day2;
elseif day1 ~= day2 && day1<=30 && day2<30
total1 = max(day1,day2);
total2 = min(day1,day2);
else
dd=-1; return
end
elseif month1 == 1 && month2 ==2
total1 = day1;
total2 = day2+31;
elseif (month1 == 2 && day1<=28) && month2 == 1
total1 = day1 + 31;
total2 = day2;
elseif (month1 == 2 && day1>28) && month2 == 1
dd=-1;
return
elseif month1 == 1 && month2 == 12
total1 = day1;
total2 = day2 + 334;
elseif month1 == 2 && month2 == 3
total1 = day1 + 31;
total2 = day2 + 59;
elseif month1 == 1 && day1<=31&& month2 == 4
total1 = day1;
total2 = day2 + 90;
elseif month1 == 1 && day1>31 && month2 == 4
dd=-1; return
elseif month1 == 11 && day1<=30 && month2 == 12
total1 = day1 ;
total2 = day2 + 30;
elseif month1 == 11 && day1>30 && month2 == 12
dd=-1;
return
elseif month1 == 7 && month2 == 9
total1 = day1 + 181;
total2 = day2 + 243;
elseif month1 == 2 && day1<=28 && month2 == 6 && day2>30
dd=-1; return
elseif month1 == 2 && day1<=28 && month2 == 6 && day2<=30
total1 = day1;
total2 = day2 + 92;
end
dd = (max(total1,total2)) - (min(total1,total2));
else
dd = -1;
return
end
end
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回答(4 个)
Image Analyst
2016-11-26
Why not make your function just be a wrapper for etime()? Did they specifically prohibit using that function?
4 个评论
Image Analyst
2017-8-26
Floor rounds down to minus infinity. Fix rounds towards zero. They give different results when operating on negative numbers.
Ugur Ulas
2017-12-29
编辑:Ugur Ulas
2017-12-29
Here there is more basic solution:
function dd = day_diff(m1, d1, m2, d2)
A = [31 28 31 30 31 30 31 31 30 31 30 31]';
day1 = d1 + sum(A(1:(m1-1)));
day2 = d2 + sum(A(1:(m2-1)));
if prod(size(m1)) ~= 1 || prod(size(m2)) ~= 1 || prod(size(d1)) ~= 1 || prod(size(d2)) ~= 1
dd = -1;
elseif m1 < 1 || m2 < 1 || d1 < 1 || d2 < 1 || m1 ~= floor(m1) || m2 ~= floor(m2) || d1 ~= floor(d1) || d2 ~= floor(d2)
dd = -1;
elseif A(m1) < d1 || A(m2) < d2
dd = -1;
else
dd = abs(day2-day1);
end
end
4 个评论
Raunil Raj
2018-3-7
Thank you for you response but I actually wanted to know the logic behind this:
elseif A(m1) < d1 || A(m2) < d2
dd = -1;
Image Analyst
2018-3-8
It says to set dd equal to minus one if A is less than d1 at the m1 index, or if A is less than d2 at the m2 index.
Vignesh M
2018-5-4
if true
function [ dd ] = day_diff( m1,d1,m2,d2 )
% Short circuiting!
N = [31,28,31,30,31,30,31,31,30,31,30,31];
if isscalar(m1) && isscalar(d1) && isscalar(m2) && isscalar(d2) && ... m1 == fix(m1) && d1 == fix(d1) && m2 == fix(m2) && d2 == fix(d2) &&... m1 > 0 && m1 <= 12 && m2 > 0 && m2 <= 12 && ... d1 > 0 && d1 <= N(m1) && d2 > 0 && d2 <= N(m2)
day1 = d1 + sum(N(1:1:m1-1));
day2 = d2 + sum(N(1:1:m2-1));
dd = abs(day1-day2)
else
dd = -1
end
end
0 个评论
RAMAKANT SHAKYA
2019-2-8
function dd=day_diff(m1,d1,m2,d2)
num_of_days=[31,28,31,30,31,30,31,31,30,31,30,31];
dd=-1;
mmm1=round(m1);mmm2=round(m2);ddd1=round(d1);ddd2=round(d2);
if(isscalar(d1)&&isscalar(d2)&&isscalar(m1)&&isscalar(m2)) % checking for valid input
if(d1-ddd1 || d2-ddd2 || m1-mmm1 || m2-mmm2) % checking for valid input
dd=-1;
else
if (m1<1||m1>12||m2<1||m2>12) %checking months
dd=-1;
else
if(d1>num_of_days(m1) || d2>num_of_days(m2) || d1<1 || d2<1) %validating days of respective month
dd=-1;
else
dd1=sum(num_of_days(1:m1));
dd1=dd1+d1-num_of_days(m1);
dd2=sum(num_of_days(1:m2));
dd2=dd2+d2-num_of_days(m2);
if(dd1>=dd2)
dd=dd1-dd2;
else
dd=dd2-dd1;
end
end
end
end
end
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