Error using containers.Map

2016 11 30
2 个回答
回答已采纳
更新时间：2017 11 3
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0 个投票

Hello, I am having following problem. I want to display single cells from my string array if my function finds a specific string. Here is the code:
function voddi_test(graph)
global vodcode
system_name = extract_system_name(graph);
variables = containers.Map();
variable = containers.Map();
keys = variables.keys;
for name = variables.keys
variable(name{1}) = true;
end
for node_name = filter_graph(graph, 'Variable', true)
node = graph(node_name{1});
for arg = node.arguments
variables([system_name '/' arg{1}]) = true;
end
end
for keys = 1:numel(variables)
if strcmp(variables(keys), 'Constant')
variables(keys{1})
else
variables(keys{2})
end
end
end
I am keeping getting the error message "Specified key type does not match the type expected for this container" when I try compare the content of the variables map with my desired strings. The code works fine, expect for the last for - loop. Any help is much appreciated, many thanks.

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Guillaume
Guillaume 2016-12-1

1 个投票

Note: I would avoid having variable names that only differ by one being plural and singular unless one was just a scalar element of the plural container.
As per Walter's answer, it seems you have not shown all the code, since your first loop is useless if the map is not filled.
Assuming the map declaration you've shown is the actual you use:
variables = containers.Map();
then it uses 'char' as the key type. However, you then have:
for keys = 1:numel(variables)
if strcmp(variables(keys), 'Constant')
There are two issues here. For starter, since variables is a map, numel(variables) is just 1. Perhaps you meant, variables.Count. Secondly, keys will be a double. As said the key type is 'char', not 'double', so you can't actually use your keys as a key into the map. Hence the error message.
Perhaphs, you meant:
for elementidx = 1 : variables.Count
if strcmp(variables.values{elementidx}, 'Constant') %if you want to compare the value
%or maybe
if strcmp(variables.keys{elementidx}, 'Constant') %if you want to compare the actual key

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jungdnb
jungdnb 2016-12-2
Thank your for the clarification. I thought since the class Map is like an array, I could use numel. I've tried your code for comparing the actual key, since this is what I need. However I am keeping getting the error message: "No method 'keys' with matching signature found for class 'containers.Map'. So I guess, you're right, my first For Loop is useless.
Guillaume
Guillaume 2016-12-2
"No method 'keys' with matching signature found for class 'containers.Map'"
That is extremely odd. keys is a method of the containers.Map class, so you should never see this message, even if you've never filled the map.
Please, show the exact code you're using.
jungdnb
jungdnb 2016-12-2
It is working now. Many Thx.
function voddi_test(graph)
global vodcode
global vod_vars
vod_vars = containers.Map();
rev_vodcode = fliplr(vodcode); %umgekehrte reihenfolge
rev_vodcode = containers.Map;
for vars_idx = 1 : vod_vars.Count
for code_idx = 1: rev_vodcode.Count
if strcmp(vod_vars.keys{vars_idx}, rev_vodcode.keys{code_idx}) %key vergleich
match = 'jo'
else
match = 'nope'
end
end
end
end
Guillaume
Guillaume 2016-12-2
Note you can get a match matrix without the loops easily in R2016b:
match = strings(vod_vars.keys).' == strings(rev_vodcode.keys)
The rows are the keys of vod_var, the columns the keys of rev_vodcode.
In version < R2016b, this would do the same:
match = bsxfun(@(r, c) strcmp(vod_vars.key{r}, rev_vodcode.keys{c}), (1:vod_vars.Count).', 1:rev_vodcode.Count)
lotus whit
lotus whit 2017-11-3
I have the same error when run the code , B1 is string like this
( 'البَهارُ' 'نبت له نور أصفر) in Arabic language , so how i can solve it?
B1=table_Ba{46};
B2= table_Ba{36};
B3=table_Ba{6};
B4=table_Ba{26};
keySet1 = {'1 0 1 0 1','1 1 1 1 1','1 0 0 0 1','1 0 0 0 0'};
valueSet1 = [B1,B2,B3,B4];
mapObj1 = containers.Map(keySet1,valueSet1)
Walter Roberson
Walter Roberson 2017-11-3
lotus whit, I am not sure what code you are running?
lotus whit
lotus whit 2017-11-3
This is my all code :
filename = 'BA.xlsx';
% [num,txt,raw] = xlsread(filename)
[~, txt] = xlsread(filename,'Sheet1');
s_t= size(txt);
for ri=1:s_t(1)
for ci=1:s_t(2)
A=txt(ri,1);
B =txt(ri,2);
table_Ba{ri} = [A B];
end
end
% B1(:,1)= A;
B1=table_Ba{46};
B2= table_Ba{36};
B3=table_Ba{6};
B4=table_Ba{26};
keySet1 = {'1 0 1 0 1','1 1 1 1 1','1 0 0 0 1','1 0 0 0 0'};
valueSet1 = [B1,B2,B3,B4];
mapObj1 = containers.Map(keySet1,valueSet1)
Walter Roberson
Walter Roberson 2017-11-3
valueSet1 = {B1,B2,B3,B4};
is my guess. If B1 and so on are character vectors, then [B1,B2,B3,B4] is a single concatenated character vector, which would not be appropriate for a list of keys like you have in keySet1.

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更多回答（1 个）

Walter Roberson
Walter Roberson 2016-11-30

0 个投票

You create variables as an empty map. It has no keys. So your first for loop does nothing so no keys are created for variable

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jungdnb
jungdnb 2016-12-1
Here is a screenshot from my matlab command line. First list are my variables.keys. Second list are the strings, in which I have to search for the variables.keys . Actually I've managed to modify the source code, so it does kind of the thing I want it to do. I want to test it for a bit, and will upload tomorrow, If I don't finde the right answer.

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