Finding values of a response within range of a cue

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I have a matrix of two columns. The first column is cue times, as in times an animal was cued to do something. The second column is times that the animal responded. If the animal correctly responded then the animal will respond within a range of .15 seconds of cue and less then 5 seconds from cue. If so this is a correct behavior and needs to go into one matrix, if not then this is an error behavior and needs to go in another matrix.
This is the code I have written, but I am not sure why exactly it is not working.
Here is my code:
data=intervals;
cue=data(:,1);
response=data(:,2);
for k=1:length(cue)
for i=1:length(response)
if cue(k)+.15 >= response(i) && cue(k)+5<= response(i)
correct(i)=response(i);
else
error(i)=response(i);
end
end
end
I attached an example matrix of intervals.
Any help would be greatly appreciated.
  3 个评论
James Tursa
James Tursa 2016-12-1
Note: error() is the name of a MATLAB intrinsic function. You should choose another name for your variable.
Krispy Scripts
Krispy Scripts 2016-12-1
Sorry about error(), I will change that.
The code fails for my criteria in that points 735.18, 1442.1, 1682.2, 1961.4, 2681.8,2682.1, 3499 should go to correct because they are after .15 seconds after and 5 seconds less then time points in first column.
Does my criteria make sense?
correct = response times greater than .15 second AND less than 5 seconds of any cue time
error = all other response times that are not correct

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采纳的回答

bio lim
bio lim 2016-12-1
编辑:bio lim 2016-12-1
Take a look at your data (which is the same as intervals).
data =
81.436 735.18
272.1 1442.1
515.3 1682.2
575.42 1961.6
734.96 2507.1
915.2 2681.8
1319.4 2682.1
1441 2777.7
1526.6 3499
1681.5 0
1961.4 0
2087 0
2372.6 0
2559.9 0
2681.7 0
2838.6 0
3049.3 0
3141 0
3322.4 0
3498.9 0
None of the data satisfies your criteria, i.e.,
if cue(k)+.15 >= response(i) && cue(k)+5<= response(i)
correct(i)=response(i);
Hence all of them would go to error.
Your program is working fine, it's that your data doesn't qualify as the correct behavior.
  4 个评论
Krispy Scripts
Krispy Scripts 2016-12-1
My apologies,
It should have been written:
if reward(i)>= (cue(k)+.15) && reward(i)<= (cue(k)+5)

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