Concatenate and extract elements of cell array to a non-cell array

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Morgan Clendennin
Morgan Clendennin 2016-12-6
编辑： Stephen23 2016-12-6
Hi,
So I am trying to take a cell array and extract the elements of it, concatenate them, and place them in the corresponding locations in a non-cell array. I'm sure that doesn't make much sense so let's say I have the follow cell array
A = {[1 3],[],[2 3 7 8];[2 4 5 7],[4 7 8],[];[],[],[]}
Now I want to take this cell array take the first element [1 3], extract the elements and concatenate them and place them as the first element of a non-cell array. This will continue for the rest of the elements of the cell array. If a cell has no elements, the corresponding location in the new array would equal zero. The final non-cell array would look like following
B = [13,0,2378;2457,478;0,0,0]

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采纳的回答

KSSV
KSSV 2016-12-6
A = {[1 3],[],[2 3 7 8];[2 4 5 7],[4 7 8],[];[],[],[]} ;
A = A(:) ;
B = zeros(size(A)) ;
for i = 1:numel(A)
if ~isempty(A{i})
B(i) = str2num(strrep(num2str(A{i}), ' ', '')) ;
end
end
B = reshape(B,3,3)
Can be achieved without loop also...but understanding is more important then code.

更多回答（1 个）

Stephen23
Stephen23 2016-12-6
编辑：Stephen23 2016-12-6
A simple solution:
>> A = {[1 3],[],[2,3,7,8];[2,4,5,7],[4,7,8],[];[],[],[]};
>> B = [13,0,2378;2457,478,0;0,0,0]
ࣳB =
13 0 2378
2457 478 0
0 0 0
>> C = cellfun(@(c)sum([0,c].*10.^(numel(c):-1:0)),A)
C =
13 0 2378
2457 478 0
0 0 0

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