How to concatenate of results from a loop

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Sunil Kunjachan
Sunil Kunjachan 2017-1-14
评论： Andrei Bobrov 2017-1-15
The output identifies the elements of X that are smaller than the product of their two indexes.
for example;
X=[1 1;0 4;6 5];
p=[];
[col,row]=size(X);
for c=1:col
for r=1:row
if (r*c)<X(r,c)
p=cat(1,p,[r c]);
else
p=[];
end
end
end
The answer should be 2 1 1 2 3 2 But I'm getting only last one i.e. 3 2. What could be wrong in my code? Please help me
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Sunil Kunjachan
Sunil Kunjachan 2017-1-15
But if you try with X=[0;1;2;3;4;5;6;7;8;9;10],the code will work.
Sunil Kunjachan
Sunil Kunjachan 2017-1-15
I'm trying to get the for X=[1 1;0 4;6 5]. I know the answer. It will be [2 1;1 2;3 2]. I'm getting only last row in that matrix.

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回答（1 个）

Andrei Bobrov
Andrei Bobrov 2017-1-14
编辑：Andrei Bobrov 2017-1-15
X=[1 1;0 4;6 5];
[r,c] = find((1:size(X,1))'*(1:size(X,2)) > X);
p = [r,c];

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