Why fprintf('%​3.1f',roun​d(-eps)) prints -0.0?

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Sandor Toth
Sandor Toth 2017-1-17
评论： James Tursa 2017-1-17
I found some very strange behaviour of the round function in Matlab R2016b (at least for me). I would expect that the round function returns 0 for -eps, but surprisingly the command:
num2hex(round(-eps))
Returns:
8000000000000000
Instead of
num2hex(0) == 0000000000000000
This causes fprintf() to print -0.0. Is this a bug or I just miss something?
  1 个评论
James Tursa
James Tursa 2017-1-17
Side Note: This seems to be consistent among the related functions ceil and fix as well. E.g.,
>> num2hex(round(-eps))
ans =
8000000000000000
>> num2hex(ceil(-eps))
ans =
8000000000000000
>> num2hex(fix(-eps))
ans =
8000000000000000

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采纳的回答

Stephen23
Stephen23 2017-1-17
编辑：Stephen23 2017-1-17
You are missing the fact that MATLAB has two zeros: positive zero and negative zero, which have different HEX values. This is a result of the IEEE 754 floating point standard that MATLAB implements, which uses one bit to indicate the number sign: a corollary of this is that even a zero can be positive or negative.
It is not possible to use < to directly test if zero is negative (by definition negative zero is equal to positive zero, so this makes sense):
>> (-0)<0
ans =
0
but here is one simple trick that will test for negative zero:
>> (1/-0)<0
ans =
1
Which relies on this behavior:
>> 1/-0
ans =
-Inf
>> 1/round(-eps) % your question
ans =
-Inf
Neat huh!
You can find more interesting information on negative zeros here:
https://en.wikipedia.org/wiki/Signed_zero

更多回答（1 个）

Adam
Adam 2017-1-17
编辑：Adam 2017-1-17

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