Finding a maximum period

4 次查看(过去 30 天)
Kate
Kate 2017-1-18
评论: Kate 2017-1-18
Hey Guys,
I'm trying to wrap my brain around how to find n maximum or minimum values in a row. I've used grpstats to generate mean values, but need to find the three highest or lowest in a row, so I can't use a sort function:
[m, g]=grpstats(data(:, 2), data(:, 1), {'mean', 'gname'})
m =
16.4605
19.6645
19.0127
20.0246
21.0003
20.0367
15.7379
22.7125
19.9485
20.4098
21.6320
17.6872
g =
'1'
'2'
'3'
'4'
'5'
'6'
'7'
'8'
'9'
'10'
'11'
'12'
Any ideas or functions to suggest? Thanks and all the best.
  2 个评论
Walter Roberson
Walter Roberson 2017-1-18
Are you looking for a moving maximum, where every point is replaced by the maximum of the point and the point before and the next point? Are you looking for a single group of three values in a row that has the highest average out of all of the sliding possibilities?
Kate
Kate 2017-1-18
The later, I'm looking for the 3 highest (or lowest) consecutive values. This is a metric called Mean Temperature of the Warmest Quarter. Thanks Walter.

请先登录,再进行评论。

采纳的回答

Image Analyst
Image Analyst 2017-1-18
If you're looking for the group of 3 elements that have the highest sum (and mean) then you can use conv() or movmean()
threeElementSum = conv(data, [1,1,1], 'same');
[maxSum, indexOfMax] = max(threeElementSum);
This will tell you where the center of the 3 element window is where the values inside that 3 element window have the highest sum of any window location in the data. Is that what you're looking for?
  1 个评论
Kate
Kate 2017-1-18
Perfect, convolution is exactly what I was looking for. I appreciate it.

请先登录,再进行评论。

更多回答(1 个)

Alexandra Harkai
Alexandra Harkai 2017-1-18
If you're looking for the n highest and lowest entry for each row of input data, you can still use the sort function:
[sorted, row_idx] = sort(data, 2);
sorted will contain the sorted data, row_idx will contain the row-wise indices, so:
sorted(:,1:n) % n smallest elements in each row
sorted(:,(end+1-n):end) % n largest elements in each row
row_idx(1,1:n) % indices in rows for the n smallest elements in each row
row_idx(1,(end+1-n):end) % indices in rows for the n largest elements in each row
  1 个评论
Kate
Kate 2017-1-18
编辑:Kate 2017-1-18
It's a great crack, but essentially I can't sort the values, because then the months are split up. Here's an example result of your code:
row_idx((end+1-n):end, 1)
ans =
5
11
8
Indicating May, November and August, which aren't proximal in time. I appreciate the help though.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Data Preprocessing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by