Variable not found in parfor loop

1 次查看（过去 30 天）
JohnDylon
JohnDylon 2017-1-20
评论： JohnDylon 2017-1-22
If I run the script:
z=1:1000;
parfor i=1:numel(z)
zfun(z(i))
end
which calls the function:
function zfun(z)
for j=1:50
for k=1:100
myz=z*10+myz*k;
end
end
save(fullfile('filepath', num2str(myz)), 'myz');
end
I get an error of Undefined function or variable 'myz' for the save command.
Any ideas how to fix this?
  2 个评论
Walter Roberson
Walter Roberson 2017-1-20
Which MATLAB version?
My spidy-senses are suggesting you might be using R2015b or R2016a but not R2016b ?
JohnDylon
JohnDylon 2017-1-20
R2016b trial for Linux. (No error for 2014a on PC though!)

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2017-1-20
You do not initialize the variable in the zfun loop.
  5 个评论
显示 3更早的评论
Walter Roberson
Walter Roberson 2017-1-21
Yes, that would have less overhead. However, due to finite precision of floating point numbers, the result of the above is going to be -inf below about -1/17 and +inf above it. The zero is at about -0.058197670686932642438500200510901 . If you were trying to find the zero, it would be much more effective to use the symbolic toolbox.
JohnDylon
JohnDylon 2017-1-22
Thank you for all valuable guidance.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by