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How to count no of iterations of first digit.

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Vishal Sharma
Vishal Sharma 2017-1-23
回答： the cyclist 2017-1-23
I want to count number of times first digit of first column is repeating. If
a = [11 3;
12 4;
13 3;
21 2;
22 5;
23 6;
24 3];
So, I want to get result in form of 1 = 3 and 2 = 4

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采纳的回答

Stephen23
Stephen23 2017-1-23
编辑：Stephen23 2017-1-23
Assuming that there are always two digits:
>> a = [11 3;
12 4;
13 3;
21 2;
22 5;
23 6;
24 3]
>> tmp = fix(a(:,1)/10);
>> uni = unique(tmp);
>> cnt = histc(tmp,uni)
cnt =
3
4
>> [uni,cnt]
ans =
1 3
2 4

更多回答（1 个）

the cyclist
the cyclist 2017-1-23
a = [11 3;
12 4;
13 3;
21 2;
22 5;
23 6;
243 3];
a1 = a(:,1);
firstDigits = floor(a1./(10.^floor(log10(a1))));
uniqueFirstDigit = unique(firstDigits);
firstDigitCount = histcounts(firstDigits,[uniqueFirstDigit; Inf])'

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