How to increase the speed of a FOR loop?

Question

EB 2017-2-6

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/323623-how-to-increase-the-speed-of-a-for-loop

回答： Ayush 2017-3-27

Hi, I have a problem with few lines of a for loop. It seems that it takes forever to finish. After one hour of waiting the for loop wasn't executed to the end, so I interrupted it manually. Also some variables within the loop are to big in size, one of them is class double 558082904 bytes and one is struct array of 4646641536 bytes in size. After this loop finishes I should have one 20x1 struct arrays with 4 fields. Each field is a matrix 33x20001x11. The other struct array is 20x1 with one field that is also 33x20001x11.

This is the code

 for p = 1:nPop
    for i=2:n
        for j = 1:length(beam_transverse);
            %Effective loads
            EffectiveLoad(p).Pe(:,i,j) = ImpactForce(:,i-1) + theta * ...
            (ImpactForce(:,i)-ImpactForce(:,i-1)) + MASS_EB_W *...
            (a0*ResponseVar(p).displ(:,i-1,j) + a2*ResponseVar(p).vel(:,i-1,j)...
            + 2*ResponseVar(p).acc(:,i-1,j)) + DAMPING_PSO(p).DAMPING_EBW_SD*(a1*...
            ResponseVar(p).displ(:,i-1,j) + 2*ResponseVar(p).vel(:,i-1,j) + ...
            a3*ResponseVar(p).acc(:,i-1,j));
            ResponseVar(p).dispth(:,i,j)=EffectiveStiff(p).Ke\EffectiveLoad(p).Pe(:,i,j);
            %Calculate the displacements, velocities and accelerations at time t+dt.
            %Calculate the reponse for every hammer impact
            %Accelerations
            ResponseVar(p).acc(:,i,j) = a4*(ResponseVar(p).dispth(:,i,j) - ResponseVar(p).displ(:,i-1,j)) + ...
            a5*ResponseVar(p).vel(:,i-1,j) + a6*ResponseVar(p).acc(:,i-1,j);
            %Velocity
            ResponseVar(p).vel(:,i,j) = ResponseVar(p).vel(:,i-1,j) + a7*(ResponseVar(p).acc(:,i,j)...
            + ResponseVar(p).acc(:,i-1,j));
            %Displacements
            ResponseVar(p).displ(:,i,j) = ResponseVar(p).displ(:,i-1,j) + dt*...
            ResponseVar(p).vel(:,i-1,j) + a8*(ResponseVar(p).acc(:,i,j) + 2*ResponseVar(p).acc(:,i-1,j));
        end
    end
 end

nPop is 20, n is 20001 and j is 11.

I am not sure that this loop is the best way of formulating my problem. Do you have any suggestions to formulate this in a different way to avoid the indefinite time for calculation to finish?

Thanks in advance!