PMSM motor controller model, rotor angle output conversion for Park transform

4 次查看(过去 30 天)
..
Hi,
I am developing a PMSM motor controller model in Simulink, I have the PMSM motor from Simpower systems, it gives the motor rotor angle in radians but when I convert it to electrical angle by multiplying by 3 for the number of pole pairs and give it to Clark and park transforms model, the results are not consistent. It gives a linear ramp, I am not sure how to interpret that, I want the conversion so that the park transform and inverse Park transform will work correctly.
Regards,
CB

采纳的回答

CB
CB 2023-1-10
Yes I think the a-phase aligned and d-q axis aligned was the issue. How do we know which one to select? can you please elaborate the difference between two alignments?
  1 个评论
Sabin
Sabin 2023-1-10
This alignment is a convention used in the model about how the angle theta is defined. This will have a big impact in the Park transform. For an overview about different axis definitions please check the FEM-Parameterized PMSM doc page. There you can see how different definitions will chnage the Park transform. Please note that in other library blocks we assume that Q leads D, the FEM-Parameterized PMSM includes also the case when D leads Q.

请先登录,再进行评论。

更多回答(1 个)

Sabin
Sabin 2023-1-9
Rotor angle can be seen as a linear ramp when rotor speed is constant. When using it in Park transform the result should be the same as when we reset the angle every 2*pi radians because we need the sin/cos(theta). I suspect the initial angle might be the root cause of mismatch or different axis definition (a-phase aligned with the d or q axis).

社区

更多回答在  Power Electronics Control

类别

Help CenterFile Exchange 中查找有关 Specialized Power Systems 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by