why I get "complex number" for the common calculation?

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vx2008
vx2008 2017-2-8
回答： John D'Errico 2017-2-8
RSTR=sum(wt.*log(rt1./rft1));
'wt', 'rt1' and 'rft1' are all real numbers and why 'RSTR' is complex numbers?
Z=log( bsxfun(@rdivide,(1+rt21),(1+rft21)) );
'rt21', and 'rft21' are both real numbers and why 'Z' is complex numbers?

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采纳的回答

John D'Errico
John D'Errico 2017-2-8
There is only one reason why you are getting a complex result there if everything is truly a real number. At least one of the elements of the set of ratios (rt21./rft21) is a negative number. It will take only one such pair that yields something negative.
log(-eps)
ans =
-36.0436533891172 + 3.14159265358979i
As you can see, the log of a negative number, even a very tiny one will have an imaginary part that is i*pi, where i is sqrt(-1).

更多回答（1 个）

Naty Shemer
Naty Shemer 2017-2-8
Most probably (rt1./rft1) is negative and the log output of a negative number is imaginary...

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