How can i decease one variable by 0.1; for increment of other variable by 0.5..?

Question

Darshan Joshi 2017-2-19

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/325847-how-can-i-decease-one-variable-by-0-1-for-increment-of-other-variable-by-0-5

评论： Matt J 2017-2-19

Say I have two variables(x&y). now for the increment of 0.5 in X; variable Y should decrease by 0.1. I have written this with IF condition. but it's lengthy. the code is as follow:

**************************************************

if temp >= 40 
    Iref=.9*AH;
end
    if temp >= 40.5 
        Iref=.8*AH;
    end
            if temp >= 41 
                Iref=.8*AH;
            end
                if temp >= 41.5 
                    Iref=.7*AH;
                end
                    if temp >= 42
                        Iref=.6*AH;
                    end
                if temp >= 42.5 
                    Iref=.5*AH;
                end
            if temp >= 43 
                Iref=.4*AH;
            end
        if temp >= 43.5
            Iref=.3*AH;
        end
    if temp >= 44 
        Iref=.2*AH;
    end    
if temp >= 44.5 
    Iref=.1*AH;
end

*******************************************************

please suggest some other short way to do this.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Matt J 2017-2-19

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/325847-how-can-i-decease-one-variable-by-0-1-for-increment-of-other-variable-by-0-5#answer_255441

编辑：Matt J 2017-2-19

在 MATLAB Online 中打开

   Iref=(  (-0.1/0.5)*(temp-40)+0.9) *AH;
   Iref=ceil(  Iref/(0.1*AH)  )*0.1*AH;

2 个评论
显示无隐藏无

Darshan Joshi 2017-2-19

it decreases constantly like a line. I want the decrement in iref after every 0.5 increment in temp. I need output like this(output of the code written in question) :

Matt J 2017-2-19

I've added a second line to discretize the output. Your plot however, does not match your code if AH is constant. Your code gives piecewise constant output whereas your plot is piecewise linear.

请先登录，再进行评论。