Divide histogram in three parts

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Nataliya
Nataliya 2017-2-28
评论： Walter Roberson 2017-2-28
Hi, I want to divide the histogram in three parts and define the ranges of three parts.
minRed = min(red(:));
maxRed = max(red(:));
AvgRed = (minRed+maxRed)/3;
AvgRed2 = AvgRed+AvgRed;
But sometimes the value of AvgRed becomes less than minRed and value of AvgRed2 exceeds the maxRed. What is the correct way to do this?

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Walter Roberson
Walter Roberson 2017-2-28
A + (B - A) /3
A + (B - A) /3 *2
  2 个评论
Nataliya
Nataliya 2017-2-28
Suppose minRed = 0.5459 and maxRed = 1. Your solution also gives AvgRed = 0.33 and AvgRed2 = 0.66. Issue still exists
Walter Roberson
Walter Roberson 2017-2-28
1-0.5459 is 0.4541. Divide by 3 gives 0.15136. Add 0.5459 gives 0.69726.

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