Divide histogram in three parts

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Nataliya 2017-2-28

评论： Walter Roberson 2017-2-28

Hi, I want to divide the histogram in three parts and define the ranges of three parts.

minRed = min(red(:));
maxRed = max(red(:));
AvgRed = (minRed+maxRed)/3;
AvgRed2 = AvgRed+AvgRed;

But sometimes the value of AvgRed becomes less than minRed and value of AvgRed2 exceeds the maxRed. What is the correct way to do this?

Walter Roberson 2017-2-28

A + (B - A) /3 
A + (B - A) /3 *2

Nataliya 2017-2-28

Suppose minRed = 0.5459 and maxRed = 1. Your solution also gives AvgRed = 0.33 and AvgRed2 = 0.66. Issue still exists

Walter Roberson 2017-2-28

1-0.5459 is 0.4541. Divide by 3 gives 0.15136. Add 0.5459 gives 0.69726.

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