check answer in range otherwise do again process with random generated number check until all digit of loop in range

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Pratik Anandpara
Pratik Anandpara 2017-3-10
评论： KSSV 2017-3-10
for k1=1:10 %set population generation limit her
pop1h(k1)=randi([200 1150],1,1 ); %random genertor limit n*3 mean n-row and 3-three colum
end
pop=pop1h*2
if pop<500;
break
else
continue
end
  1 个评论
Pratik Anandpara
Pratik Anandpara 2017-3-10
pop1h generate 10 random number from 200 to 1150 now need to check this answer pop=pop1h*2 if this answer is<500 than not valid again new 10 digit generate and do same process untill condition satisfy

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KSSV
KSSV 2017-3-10
for k1=1:100 %set population generation limit her
pop1h=randi([200 1150],1,1 ); %random genertor limit n*3 mean n-row and 3-three colum
pop=pop1h*2 ;
if pop<500;
disp('condition satisfied loop exited') ;
break
else
continue
end
end
  7 个评论
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Pratik Anandpara
Pratik Anandpara 2017-3-10
i want final answer in 10 digit array after put value in equation POP=POP1H*2... and all 10 digit follow --pop>500 after got 10 digit in this range stop
KSSV
KSSV 2017-3-10
count = 0 ;
N = 10 ;
iwant = zeros(N,1) ;
for k1=1:100 %set population generation limit her
pop1h=randi([200 1150],1,1 ); %random genertor limit n*3 mean n-row and 3-three colum
pop=pop1h*2 ;
if pop > 500;
count = count+1 ;
iwant(count) = pop ;
if count == N
break
end
else
continue
end
end
This can be achieved without loop also

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