How does 6.022140857*10^23 differ from 6.022140857e+23?
1 次查看(过去 30 天)
显示 更早的评论
In matlab if I write the following script I get a non-zero answer which is awkward, can somebody please explain this?
av = 6.022140857*10^23;
av_1 = 6.022140857e+23;
diff = av - av_1
The answer I get is
diff =
-67108864
0 个评论
采纳的回答
Stephen23
2017-3-10
编辑:Stephen23
2017-3-10
>> fprintf('%.0f\n',av)
602214085699999950000000
>> fprintf('%.0f\n',av_1)
602214085700000020000000
because X*B^P performs two numeric operations on three floating point values and accumulates floating point error with each operation. XeP generates the value directly, without any numeric operations.
Because of this:
Or any of the thousand other threads explaining floating point errors and how they accumulate during numeric operations.
You might also be interested in trying James Tursa's excellent FEX submission:
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!