how do i use textscan to display strings have spaces in between ?

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chocho
chocho 2017-3-22
评论： chocho 2017-3-22
Hi friends, i have used this code with textscan:
fidpw= fopen('yy.txt','rt');
format = repmat('%s ',[1 row1]);
Pat = textscan(fidpw,format );
fclose(fidpw);
i used texscan to display the columns in this file but it doesn't work well because of the space existed in between the first rows of its corresponding columns
the columns looks like :
col1={stage iiib;t3;n1;m0}
col2={stage iv;t4;n1;m1}
code output looks like:
col1={stage;stage;t3;n1;m0}
col2={iiib;iv;t4;n1;m1}
?????
is this because i used %s in textscan ???
Thanks in advance!

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采纳的回答

Walter Roberson
Walter Roberson 2017-3-22
In that situation, you should
Pat = textscan(fidpw, format, 'whitespace', '', 'delimiter', ';');
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Walter Roberson
Walter Roberson 2017-3-22
ncol = 12;
fmt = repmat('%s', 1, ncol);
fid = fopen('Classeur1.txt', 'rt');
Pat = textscan(fid, fmt, 'Delimiter', '\t');
fclose(fid)
chocho
chocho 2017-3-22
@ Walter Roberson Great bro!
Works Well. the key point is the delimiter '\t'
Appreciate your help! Always perfect answers from you .

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更多回答（1 个）

KSSV
KSSV 2017-3-22
fid = fopen('my text file','r');
S = textscan(fid,'%s','delimiter','\n') ;
fclose(fid) ;
S = S{1} ;
Note that S will be a cell. You can access your required line using S{i} . Where i is your line number.
  1 个评论
chocho
chocho 2017-3-22
code bug Error using textscan Buffer overflow (bufsize = 4095) while reading string from file (row 1 u, field 1 u). Use 'bufsize' option. See HELP TEXTSCAN. iic stage iia stage i stage iiic stage i stage iva stage iia stage iia stage i stage iii stage ii stage iv stage iiic stage iia stage iv stage iib NA stage iiib stage iiib stage iii stage iv stage iii
Error in Comparison (line 82) Patient = textscan(fidpw,'%s','delimiter','\n') ;

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