Mean Amplitude of the signal
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Hi, My problem is to calculate mean amplitude of the signal and plot it on the graph with signal course. Below you can see my source code:
y % signal vector, where [3083 1]= size(y)
Fs=100;
L=length(y);
NFFT = 2^nextpow2(L);
Y = fft(y,NFFT)/L;
f = Fs/2*linspace(0,1,NFFT/2+1);
n1=1/100; %1
m1=L/100; %end
[a b]=size(y);
nov=(m1-n1)/(a-1);
x=n1:nov:m1;
figure
subplot(2,1,1)
plot(f,2*abs(Y(1:NFFT/2+1)),color) % amplitude spectrum
subplot(2,1,2)
plot(x,y,'b') % course of the signal
Could you tell me how can I calculated mean amplitude based on this? Or maybe there exists another way to find it? When I used mean(abs(Y(1:NFFT/2+1))) and ploted it on the second subplot it was far away from signal...
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Arun Aniyan
2012-3-23
Hi,
I am not sure why you should do fourier transform to get the mean amplitude of your signal . For the mean amplitude of the signal for your case you can simply use
mean_amplitude = mean(y); % Find mean amplitude
d=ones(1,length(y)).*mean_amplitude; % A dummy vector having values of the mean
plot(x,y); % Plot your signal
hold all;
plot(d);
This will give a plot with the signal , with a straight line over plotted along the signal. Or do you mean , the mean amplitude of the spectrum ?
Cheers
- Arun
Wayne King
2012-3-23
Hi Karolina, You can find the average power of the signal in the [3,10] Hz band. If you have the Signal Processing Toolbox.
Fs = 100;
t = 0:0.01:1-0.01;
x = cos(2*pi*4*t)+1/2*sin(2*pi*8*t)+randn(size(t));
psdest = psd(spectrum.periodogram,x,'Fs',100,'NFFT',length(x));
pwr = avgpower(psdest,[3,10]);
You can also easily obtain what percentage of the power is contained in that interval
pwrratio = 100*(pwr/avgpower(psdest,[0,50]));
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