How to modify a struct and create a new struct out of it?

Question

Rightia Rollmann 2017-4-4

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/333622-how-to-modify-a-struct-and-create-a-new-struct-out-of-it

回答： James Tursa 2017-4-4

I want to get Cartesian coordinates from struct A

A(1).X = 1;
A(1).Y = 2;
A(1).Z = 3;
A(2).X = 4;
A(2).Y = 5;
A(2).Z = 6;

and change them to spherical coordinates in degrees and put them in struct B

for i = 1:length(A)
[theta,phi, r] = cart2sph(A(i).X, A(i).Y, A(i).Z);
B(i).theta = rad2deg(theta);
B(i).phi = rad2deg(phi);
B(i).r = r;
end

so I will finally get:

B(1).theta = 63.43;
B(1).phi = 53.30;
B(1).r = 3.7;
B(2).theta = 51.34;
B(2).phi = 43.13;
B(2).r = 8.77;

What is to shortest way to achieve it? For example, something without using this annoying for loop.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

James Tursa 2017-4-4

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/333622-how-to-modify-a-struct-and-create-a-new-struct-out-of-it#answer_261755

在 MATLAB Online 中打开

One way, but note there will be loops in the background:

X = [A.X];
Y = [A.Y];
Z = [A.Z];
[theta,phi,r] = cart2sph(X, Y, Z);
THETA = num2cell(rad2deg(theta));
PHI = num2cell(rad2deg(phi));
R = num2cell(r);
n = numel(A);
[B(1:n).theta] = deal(THETA{:});
[B(1:n).phi] = deal(PHI{:});
[B(1:n).r] = deal(R{:});

Also, note that keeping each individual number as its own field in a struct is not a very memory efficient way of storing your data. Unless you need the data in this format for some other reason, it would be better to simply keep the data as double arrays (e.g., like the X, Y, and Z arrays).