Results showing up as NaN

5 次查看(过去 30 天)
I have been working on a launch control simulation and something happened recently because the matrix z is returning only NaN values now... I do not remember changing anything in the script or the function. I have also attached below the main function used with the code... maybe you spot a mistake there...
global m g I h lR lF r LCREV_MAX LCSPEED_MAX
LCREV_MAX = 12000;
LCSPEED_MAX = 35;
m = 295; % mass of vehicle including driver
g = 9.81; % gravitational acceleration
r = 0.23; % wheel radius
I = 0.2645; % tyre moment of inertia
h = 0.28; % CoG height
lR = 0.765; % Distance of CoG to rear axle
lF = 0.765; % Distance of CoG to front axel
z10 = 0; % initial x position
z20 = 0; % initial linear velocity
z30 = 0; % initial angle of rear wheel
z40 = 0; % intial angular velocity of rear wheel
z0 = [z10 z20 z30 z40]; % initial conditions vector
t0 = 0; % intial time
tf = 6; % final time
[t,z] = ode45('LC_eom',(t0:0.1:tf),z0);
x = z(:,1); % position as first column of z matrix
v = z(:,2); % linear velocity as second column of z matrix
theta = z(:,3); % angle as third column of z matrix
omega = z(:,4); % angular velocity as fourth column of z matrix
  8 个评论
Andrew Newell
Andrew Newell 2017-4-20
编辑:Andrew Newell 2017-4-20
One reason you may be using global variables is that ode45 expects a function with two variables. However, that is easily handled using anonymous functions. For example, the function LC_eom needs m, I and r in addition to t and z. However, these are just parameters that (I presume) aren't changing while ode45 is running. You can define
function dz = LC_eom (t,z,m,I,r,)
in LC_eom.m and then, LCS.m, define
fun = @(t,z) LC_eom(t,z,m,I,r);
and use that in ode45:
[t,z] = ode45(fun,(t0:0.1:tf),z0);
Alexandru Bortea
Alexandru Bortea 2017-4-20
Thank you very much for all the answers, I'll try to remove all global parameters and individually use them in the functions.

请先登录,再进行评论。

采纳的回答

Andrew Newell
Andrew Newell 2017-4-20
Here is one source of NaN's: In slipratio_fun with the initial value of t=0 and v=0, you have omega=v=0. The line
sx (abs(omega)*r>=abs(v)) = -1 + v./(omega.*r); % acceleration
sets sz equal to NaN because it's dividing by zero.
  7 个评论
Alexandru Bortea
Alexandru Bortea 2017-4-20
I should be able to deal with it myself! Thank you very much for helping me with the code part!!!
Andrew Newell
Andrew Newell 2017-4-20
You're welcome. Glad to help!

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by