Hough Transform source code explanation

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Ba Ba Black Sheep!
Ba Ba Black Sheep! 2017-4-22
回答： Walter Roberson 2017-4-22
I couldn't understand the following code's for loop.
What is the purpose of the for loop here?
Why is for iterating from 7 to 7?
And, why is num_peak = 3?
clc
close all
clear all
imageCaption = sprintf('scratchedImage.jpg');
inputOriginalImage = imread(imageCaption);
inputOriginalImageGrayscale = rgb2gray(inputOriginalImage);
completelyPreprocessedImage = Preprocessing( inputOriginalImage );
N = 12;
bandpassFilteredImage = BandpassFiltering(completelyPreprocessedImage, N);
[ROWS, COLS, k] = size(bandpassFilteredImage);
homomorphicFilteredImage = HomomorphicFiltering(bandpassFilteredImage, N);
num_peak=3;
length_line=[];
for n=7:7
inputImageForHaughtTransform = bwareaopen( homomorphicFilteredImage(:,:,n),20);
[houghtTransformMatrix, theta, rho] = hough(inputImageForHaughtTransform);
imshow(houghtTransformMatrix,[],'XData',theta,
'YData',rho,'InitialMagnification','fit');
xlabel('\theta'), ylabel('\rho');
axis on, axis normal, hold on;
peaks = houghpeaks(houghtTransformMatrix,3,'threshold',
ceil(0.3*max(houghtTransformMatrix(:))));
x = theta(peaks(:,2));
y = rho(peaks(:,1));
plot(x,y,'s','color','white');
foundLinesInHoughOperation = houghlines(inputImageForHaughtTransform,
theta, rho, peaks,'FillGap',
5,'MinLength',7);
figure, imshow(completelyPreprocessedImage), hold on
MarkLines(foundLinesInHoughOperation, COLS, x, y);
end

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采纳的回答

Walter Roberson
Walter Roberson 2017-4-22
We do not know. The routines Preprocessing(), BandpassFiltering(), and HomomorphicFiltering() are not Mathworks routines, and they do not appear to be anywhere in a File Exchange contribution either. We do not know what they do.
http://blogs.mathworks.com/steve/2013/06/25/homomorphic-filtering-part-1/

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