How can I access the previous index of a vector?

Question

Khalid Khawaja 2017-4-24

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评论： Khalid Khawaja 2017-4-24

Hello friends,

I am trying to write a code to generate random vectors. Some of the variables are integer whereas a few are real numbers. Following is the code:

xL=[1 500 1 500];
xU=[37 1400 37 1400];
Xint=[1 3];
nvar=4;
for xV=1:nvar
if Xint(xV)==xV
         InPoP(:,xV) = randi([xL(xV) xU(xV)],Popu_size,1); 
      else
InPoP(:,xV) = (xU(xV)-xL(xV)).*rand(Popu_size,1) + xL(xV);
    end
end

Xint vector shows that first and third elements should be generated as integer. The problem is when the loop moves away from x=2. It cannot access the elements of Xint to know the number. I would be grateful if someone can share the solution of the problem.

Regards

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KSSV 2017-4-24

You have in Xint only two numbers and you are trying to access four numbers out of it. Make Xint to have four numbers i.e include few more numbers.

Khalid Khawaja 2017-4-24

How can I write a program to generate Xint variables integer using iterative schemes?

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Answer 1

Walter Roberson 2017-4-24

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Change

if Xint(xV)==xV

to

if ismember(xV, Xint)

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Khalid Khawaja 2017-4-24

Thank you very much for the answer. I was looking for exactly the same thing. Regards

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Answer 2

Roger Stafford 2017-4-24

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You don’t appear to use ‘Xint’ for any other purpose than deciding whether to use integers or reals. Therefore I suggest you change it to:

   Xint = [1 0 1 0];
   for xV=1:nvar
     if Xint(xV) == 1
       % Use integers
     else
       % Use reals
     end

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Khalid Khawaja 2017-4-24

Thank you for your answer. It is also a good solution. Actually, I need Xint values for further operations. Changing the values to binary will need many changes in my code. Regards

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