rgb to gray image indeces matching

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Sokhib Tukhtayev 2017-4-27

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https://ww2.mathworks.cn/matlabcentral/answers/337601-rgb-to-gray-image-indeces-matching

评论： Sokhib Tukhtayev 2017-5-6

I have an RGB color image with dimensions: 460x640x3 and a gray image with the same dimensions: 460x640. They are of the same type, that is, uint8. I want to get the intensity information of the gray image using the coordinate values from color image if that coordinate value is not black (intensity value ~= 0). if not the intensity value of gray image should be 0 (black).

If I loop through each values for example like below:

img_length = 460x640;
for i = 1:img_length
if rgbImage(i) ~= 0;
depthImage(i) = i; 
else if rgbImage(i) == 0;
depthImage(i) = 0;
i = i+1;
end;

As for color image how can I use only large dimensions as if it is a gray image?

2 个评论
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Adam 2017-4-27

Don't call a variable length, it is a builtin function that you just over-rode.

Sokhib Tukhtayev 2017-4-27

编辑：Sokhib Tukhtayev 2017-4-27

ok, it is just for reference, it could be any name. I changed it. Thank you, by the way!

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回答（1 个）

Image Analyst 2017-4-27

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/337601-rgb-to-gray-image-indeces-matching#answer_264739

编辑：Image Analyst 2017-4-27

在 MATLAB Online 中打开

Try this:

sumImage = rgbImage(:,:,1) + rgbImage(:,:,2) + rgbImage(:,:,3);
mask = sumImage == 0;
grayValues = grayImage(mask); % 1-d list of gray levels where the color image is black.

6 个评论
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Image Analyst 2017-5-4

I don't understand how it does not do what you want. First it finds all the locations (pixels) where the image is totally black - each of red, green, and blue is exactly zero. Then it gives you the gray levels from the gray scale image at those locations. Your code does nothing like that (nothing like what you asked for) whereas mine does.

Sokhib Tukhtayev 2017-5-6