How to make a DropDown function control the visibility of a spinner in App designer

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anja pedersen
anja pedersen 2017-4-27
回答： Tushar Upadhyay 2017-5-2
Hi,
I am New to App Designer and i would like to make one item in the DroppDown function to make a spinner visible. Is this possible? What I have tried so far is this:
Value= app.InstrumentDropDown.Value;
if Value==1
app.AntalldypSpinner.Visible='off'
elseif Value==2
app.instrument='D';
app.AntalldypSpinner.Visible='on'
elseif Value==3
app.instrument='D';
app.AntalldypSpinner.Visible='off'
elseif Value==4
app.instrument='R';
app.AntalldypSpinner.Visible='off'
end
but this only make the spinner disappear and it never shows up again. Can someone help me?

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回答（1 个）

Tushar Upadhyay
Tushar Upadhyay 2017-5-2
The app.InstrumentDropDown.Value might be giving value in "char" instead of numeric. Make sure that the value is numeric. If it is a char then change the If statement as below:
if Value=='1' app.AntalldypSpinner.Visible='off'
If that does not work, then add the debug point in the function and see if it is going into the appropriate conditional statement.

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