Randomly change the location of 1s on a matrix of 0s (randperm on a matrix}

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Doobie
Doobie 2017-4-29
回答： Image Analyst 2017-4-29
How does one generate a random matrix that satisfies certain properties? Specifically, I'm looking for a code that does this:
Given the matrix below, I want to randomly change the locations of 1s.
1 0 0
1 0 0
0 0 0
0 0 0
So examples would be
1 0 0 0 0 0 0 0 1
0 1 0 0 0 0 0 0 0
0 0 0 0 1 0 1 0 0
0 0 0 1 0 0 0 0 0
Well the initial matrix is easy enough.
A = zeros(4,3);
A(1:2,1) = ones(2,1);
But I don't know how to proceed from here. randperm() only generates a vector so doesn't work here. Is there a matlab function that does what randperm does on a matrix?

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采纳的回答

Image Analyst
Image Analyst 2017-4-29
Here's one way:
m=[...
1 0 0
1 0 0
0 0 0
0 0 0]
[rows, columns] = size(m);
ne = numel(m)
numOnes = sum(m(:))
% Generate 10 new versions with 1's in different locations each time.
for k = 1 : 10
m2 = zeros(size(m)); % Initialize
m2(randperm(ne, numOnes)) = 1;
% Turn from vector into 2-D matrix
m2 = reshape(m2, rows, columns)
end

更多回答（1 个）

Star Strider
Star Strider 2017-4-29
See How to place a number in a random position in a matrix of zeros? (link) for one approach. You can create more random 1 values by having the randi function return a vector rather than a single value. See the documentation for the randi function for details.

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