The 'table' format doesn't support 'find', so I will keep the two columns as separate files. In which case I need to find the row dependant on month, and then find the corresponding value matching that row within the separate column of numbers
finding rows which correspond to date
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I have a table of data with two columns, one with monthly averaged data values and the other with the corresponding month and year in datetime 'MMM yyyy' format, e.g.
Jan 2004 26.3
Mar 2004 27.2
Jun 2004 35.5
Jan 2006 45.1
Mar 2007 32.2
How can I select each row beginning with a specific month eg. March (for each year), to then average these and get a representative average for that month over the full time span?
Many thanks!
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Peter Perkins
2017-5-16
Dom, you're right that you can't call find on a table, but you can call find on a variable in a table.
find(month(t.Date) == 3)
for example. But usually, you don't want to call find anyway (leave it as a logical)
t(month(t.Date) == 3,:)
And in this case, grouped calculations are already provided as part of varfun.
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Peter Perkins
2017-5-16
>> Date = datetime({'Jan 2004';'Mar 2004';'Jun 2004';'Jan 2006';'Mar 2007'},'Format','MMM yyyy');
>> Value = [26.3;27.2;35.5;45.1;32.2];
>> t = table(Date,Value)
t =
5×2 table
Date Value
________ _____
Jan 2004 26.3
Mar 2004 27.2
Jun 2004 35.5
Jan 2006 45.1
Mar 2007 32.2
>> t.Month = month(t.Date,'shortname')
t =
5×3 table
Date Value Month
________ _____ _____
Jan 2004 26.3 'Jan'
Mar 2004 27.2 'Mar'
Jun 2004 35.5 'Jun'
Jan 2006 45.1 'Jan'
Mar 2007 32.2 'Mar'
>> monthly = varfun(@mean,t,'GroupingVariable','Month','InputVariable','Value')
monthly =
3×3 table
Month GroupCount mean_Value
_____ __________ __________
'Jan' 2 35.7
'Jun' 1 35.5
'Mar' 2 29.7
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