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How to plus two nan matrix

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min wong
min wong 2017-5-16
评论： James Tursa 2018-11-28
If my two matrix are
a=3*3,b=3*3,c=3*3
a=[1 2 3,4 5 nan,7 nan 9]
b=[nan 3 3,4 5 6,nan 8 9]
c=a+b
Is that possible that c=[1 5 6,8 10 6,7 8 18]
How to calculate?
Thanks

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采纳的回答

James Tursa
James Tursa 2017-5-16
c = a + b;
c(isnan(c)) = a(isnan(c));
c(isnan(c)) = b(isnan(c));
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James Tursa
James Tursa 2017-5-17
Depending on what you want to have happen to the "NaN" spots, I am guessing you will want either
c = (a + b)/2;
c(isnan(c)) = a(isnan(c));
c(isnan(c)) = b(isnan(c));
or
c = (a + b)/2;
c(isnan(c)) = a(isnan(c))/2;
c(isnan(c)) = b(isnan(c))/2;

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更多回答（2 个）

Paulo Neto
Paulo Neto 2018-11-28
Hi James Tursa,
How I can do this: c = (a + b)/b
Regards
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Paulo Neto
Paulo Neto 2018-11-28
I'm considering a and b as arrays:
a=3*3,b=3*3,c=3*3
a=[1 2 3,4 5 nan,7 nan 9]
b=[nan 3 3,4 5 6,nan 8 9]
To calculate c = a + b, I'm using your routine:
c(isnan(c)) = a(isnan(c));
c(isnan(c)) = b(isnan(c));
and results in c=[1 5 6,8 10 6,7 8 18]
But I need to calculate: (a+b)./b, can I use the same method?
James Tursa
James Tursa 2018-11-28
What would you want the individual result to be if "a" is NaN, and if "b" is NaN?

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Paulo Neto
Paulo Neto 2018-11-28
I'm considering a and b as arrays:
a=3*3,b=3*3,c=3*3
a=[1 2 3,4 5 nan,7 nan 9]
b=[nan 3 3,4 5 6,nan 8 9]
To calculate c = a + b, I'm using your routine:
c(isnan(c)) = a(isnan(c));
c(isnan(c)) = b(isnan(c));
and results in c=[1 5 6,8 10 6,7 8 18]
But I need to calculate: (a+b)./b, can I use the same method?

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