Interp3 Producing Unexpected Output?

1 次查看(过去 30 天)
Hello,
When using the default trilinear interpolation of interp3, I'm getting an unexpected output:
>> Interpval = interp3(X,X,X,V,X(10),X(5),X(1))
Interpval =
2.373878950731685e+04
>> V(10,5,1)
ans =
2.423129551369272e+04
where X is an n x 1 vector, and V is an n x n x n matrix.
I expected the two results to match as it should notice that the interpolation point is a grid point.
Why do the results not match?
Hopefully I'm just tired and this is a trivial question.
Thanks for your time and help.

采纳的回答

Walter Roberson
Walter Roberson 2017-5-20
>> X = sort(randn(1,25));
>> V = rand(25,25,25);
>> Interpval = interp3(X,X,X,V,X(10),X(5),X(1))
Interpval =
0.505428142457703
>> V(10,5,1)
ans =
0.844855674576263
>> V(5,10,1)
ans =
0.505428142457703
In other words, confusion over the fact that interp3's first coordinate is X, second coordinate is Y, whereas indexing in MATLAB has first coordinate corresponding to Y and second coordinate corresponding to X.
  1 个评论
John Chilleri
John Chilleri 2017-5-20
This was the case - I wasn't thinking about grids, I was thinking about 3D space. Row and column formatting switch the X and Y...
Thank you!

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Interpolation 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by