Info

此问题已关闭。 请重新打开它进行编辑或回答。

how to simulate a function

1 次查看(过去 30 天)
Fatma Abdullah
Fatma Abdullah 2017-5-31
关闭: Stephen23 2017-5-31
i'm trying to simulate this function "pd" against "lnd" by accept reject monte carlo method but it takes forever and nothing comes out
M=8;
N=32;
K=14;
c=2;
s=1;
T=18.623390280430364437245197384232;
lnd=0:5:30;
pd1=(2*K*nchoosek(N/2,K)*((gamma(K+i)*gamma(N-K+i+1+T./(1+lnd)))./(gamma(N+1+T./(1+lnd)))-...
(symsum(nchoosek(N/2,i)*(gamma(K+i)*gamma(N-K-i+1+T./(1+lnd)))./(gamma(N+1+T./(1+lnd))), i, K, (N/2)))));
%lnd=0:5:30;
pd=(symsum(nchoosek(M,i)*(pd1).^(i).* (1-(pd1)).^(M-i), i, s, M));
O=10^7;
Mx=1.2*max(pd);
lndi=10*rand(1,O);
pj=10*rand(1,O);
pd1i=2*K*nchoosek(N/2,K)*((gamma(K+i)*gamma(N-K+i+1+T./(1+lndi)))./(gamma(N+1+T./(1+lndi)))-...
(symsum(nchoosek(N/2,i)*(gamma(K+i)*gamma(N-K-i+1+T./(1+lndi)))./(gamma(N+1+T./(1+lndi))), i, K, (N/2))));
f_lndi=(symsum(nchoosek(M,i)*(pd1i).^(i)* (1-(pd1i)).^(M-i), i, s, M));
comp=pj*Mx;
result=f_lndi>=comp;
index=find(result);
lnd_new=lndi(1,index);
[pd1,lnd1]=hist(lnd_new,100);
dlnd=(lnd1(2)-lnd1(1));
h=(pd1/length(lnd_new))/dlnd;
plot(lnd1,h,'b.');

回答(1 个)

Walter Roberson
Walter Roberson 2017-5-31
As I told you in https://www.mathworks.com/matlabcentral/answers/342612-why-does-it-take-forever-to-solve-a-function, do not use symsum() for adding definite symbolic terms.

此问题已关闭。

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by